1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$2 \frac { 4 } { 6 } - \frac { 6 } { 3 } + 6 \frac { 2 } { 2 } =$$

Evaluate

$\frac{23}{3}\approx 7.666666667$

Solution Steps

Multiply $2$ and $6$ to get $12$.

$$\frac{12+4}{6}-\frac{6}{3}+\frac{6\times 2+2}{2}$$

Add $12$ and $4$ to get $16$.

$$\frac{16}{6}-\frac{6}{3}+\frac{6\times 2+2}{2}$$

Reduce the fraction $\frac{16}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{8}{3}-\frac{6}{3}+\frac{6\times 2+2}{2}$$

Since $\frac{8}{3}$ and $\frac{6}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-6}{3}+\frac{6\times 2+2}{2}$$

Subtract $6$ from $8$ to get $2$.

$$\frac{2}{3}+\frac{6\times 2+2}{2}$$

Multiply $6$ and $2$ to get $12$.

$$\frac{2}{3}+\frac{12+2}{2}$$

Add $12$ and $2$ to get $14$.

$$\frac{2}{3}+\frac{14}{2}$$

Divide $14$ by $2$ to get $7$.

$$\frac{2}{3}+7$$

Convert $7$ to fraction $\frac{21}{3}$.

$$\frac{2}{3}+\frac{21}{3}$$

Since $\frac{2}{3}$ and $\frac{21}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{2+21}{3}$$

Add $2$ and $21$ to get $23$.

$$\frac{23}{3}$$

Show Solution

Factor

$\frac{23}{3} = 7\frac{2}{3} = 7.666666666666667$