How to solve 2- 2- 2-2 2 + 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2- 2- 2-2 2 + 2 | Equatix

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3(r+2s)=2t-4

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Question

$$2 - [ 2 - \{ 2 - 2 ( 2 + 2 ) \} ]$$

Evaluate

$-6$

Solution Steps

Add $2$ and $2$ to get $4$.

$$2-\left(2-\left(2-2\times 4\right)\right)$$

Multiply $2$ and $4$ to get $8$.

$$2-\left(2-\left(2-8\right)\right)$$

Subtract $8$ from $2$ to get $-6$.

$$2-\left(2-\left(-6\right)\right)$$

The opposite of $-6$ is $6$.

$$2-\left(2+6\right)$$

Add $2$ and $6$ to get $8$.

$$2-8$$

Subtract $8$ from $2$ to get $-6$.

$$-6$$

Show Solution

Factor

$-6$

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