Solve 2-{1-[0-(3\times3\div-9-4-4)-6\div2\times-2]+7\times4}

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Question

$$2- \{ 1-[0-(3 \times 3 \div -9-4-4)-6 \div 2 \times -2]+7 \times 4 \}$$

Evaluate

$-12$

Solution Steps

Multiply $3$ and $3$ to get $9$.

$$2-\left(1-\left(0-\left(\frac{9}{-9}-4-4\right)-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

Divide $9$ by $-9$ to get $-1$.

$$2-\left(1-\left(0-\left(-1-4-4\right)-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

Subtract $4$ from $-1$ to get $-5$.

$$2-\left(1-\left(0-\left(-5-4\right)-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

Subtract $4$ from $-5$ to get $-9$.

$$2-\left(1-\left(0-\left(-9\right)-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

The opposite of $-9$ is $9$.

$$2-\left(1-\left(0+9-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

Add $0$ and $9$ to get $9$.

$$2-\left(1-\left(9-\frac{6}{2}\left(-2\right)\right)+7\times 4\right)$$

Divide $6$ by $2$ to get $3$.

$$2-\left(1-\left(9-3\left(-2\right)\right)+7\times 4\right)$$

Multiply $3$ and $-2$ to get $-6$.

$$2-\left(1-\left(9-\left(-6\right)\right)+7\times 4\right)$$

The opposite of $-6$ is $6$.

$$2-\left(1-\left(9+6\right)+7\times 4\right)$$

Add $9$ and $6$ to get $15$.

$$2-\left(1-15+7\times 4\right)$$

Subtract $15$ from $1$ to get $-14$.

$$2-\left(-14+7\times 4\right)$$

Multiply $7$ and $4$ to get $28$.

$$2-\left(-14+28\right)$$

Add $-14$ and $28$ to get $14$.

$$2-14$$

Subtract $14$ from $2$ to get $-12$.

$$-12$$

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