Solve 2-3\times[-2+10-4\times(-1+3/3)-8]-2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2-3 \times [-2+10-4 \times (-1+3/3)-8]-2$$

Evaluate

$0$

Solution Steps

Divide $3$ by $3$ to get $1$.

$$2-3\left(-2+10-4\left(-1+1\right)-8\right)-2$$

Add $-2$ and $10$ to get $8$.

$$2-3\left(8-4\left(-1+1\right)-8\right)-2$$

Add $-1$ and $1$ to get $0$.

$$2-3\left(8-4\times 0-8\right)-2$$

Multiply $4$ and $0$ to get $0$.

$$2-3\left(8-0-8\right)-2$$

Subtract $0$ from $8$ to get $8$.

$$2-3\left(8-8\right)-2$$

Subtract $8$ from $8$ to get $0$.

$$2-3\times 0-2$$

Multiply $3$ and $0$ to get $0$.

$$2-0-2$$

Subtract $0$ from $2$ to get $2$.

$$2-2$$

Subtract $2$ from $2$ to get $0$.

$$0$$

Factor

$0$