Solve 2-4-(-6-3)-(2-(-2+(-5+3))-1)+2= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2-4-(-6-3)-(2-(-2+(-5+3))-1)+2=$$

Evaluate

$4$

Solution Steps

Subtract $4$ from $2$ to get $-2$.

$$-2-\left(-6-3\right)-\left(2-\left(-2-5+3\right)-1\right)+2$$

Subtract $3$ from $-6$ to get $-9$.

$$-2-\left(-9\right)-\left(2-\left(-2-5+3\right)-1\right)+2$$

The opposite of $-9$ is $9$.

$$-2+9-\left(2-\left(-2-5+3\right)-1\right)+2$$

Add $-2$ and $9$ to get $7$.

$$7-\left(2-\left(-2-5+3\right)-1\right)+2$$

Subtract $5$ from $-2$ to get $-7$.

$$7-\left(2-\left(-7+3\right)-1\right)+2$$

Add $-7$ and $3$ to get $-4$.

$$7-\left(2-\left(-4\right)-1\right)+2$$

The opposite of $-4$ is $4$.

$$7-\left(2+4-1\right)+2$$

Add $2$ and $4$ to get $6$.

$$7-\left(6-1\right)+2$$

Subtract $1$ from $6$ to get $5$.

$$7-5+2$$

Subtract $5$ from $7$ to get $2$.

$$2+2$$

Add $2$ and $2$ to get $4$.

$$4$$

Factor

$2^{2}$