$$2(1+b)=125cm$$
$b=\frac{125cm}{2}-1$
$$2+2b=125cm$$
$$2b=125cm-2$$
$$\frac{2b}{2}=\frac{125cm-2}{2}$$
$$b=\frac{125cm-2}{2}$$
$$b=\frac{125cm}{2}-1$$
Show Solution
Hide Solution
$\left\{\begin{matrix}c=\frac{2\left(b+1\right)}{125m}\text{, }&m\neq 0\\c\in \mathrm{R}\text{, }&b=-1\text{ and }m=0\end{matrix}\right.$
$$125cm=2+2b$$
$$125mc=2b+2$$
$$\frac{125mc}{125m}=\frac{2b+2}{125m}$$
$$c=\frac{2b+2}{125m}$$
$$c=\frac{2\left(b+1\right)}{125m}$$
