How to solve 2(1 + x) = 9x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(1 + x) = 9x | Equatix

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$$2(1+x)=9x$$

$x=\frac{2}{7}\approx 0.285714286$

Use the distributive property to multiply $2$ by $1+x$.

$$2+2x=9x$$

Subtract $9x$ from both sides.

$$2+2x-9x=0$$

Combine $2x$ and $-9x$ to get $-7x$.

$$2-7x=0$$

Subtract $2$ from both sides. Anything subtracted from zero gives its negation.

$$-7x=-2$$

Divide both sides by $-7$.

$$x=\frac{-2}{-7}$$

Fraction $\frac{-2}{-7}$ can be simplified to $\frac{2}{7}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{2}{7}$$