Solve 2(2x+3)-10 < 6(x-2) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2(2x+3)-10 < 6(x-2)$$

Solve for x

$x>4$

Solution Steps

Use the distributive property to multiply $2$ by $2x+3$.

$$4x+6-10<6\left(x-2\right)$$

Subtract $10$ from $6$ to get $-4$.

$$4x-4<6\left(x-2\right)$$

Use the distributive property to multiply $6$ by $x-2$.

$$4x-4<6x-12$$

Subtract $6x$ from both sides.

$$4x-4-6x<-12$$

Combine $4x$ and $-6x$ to get $-2x$.

$$-2x-4<-12$$

Add $4$ to both sides.

$$-2x<-12+4$$

Add $-12$ and $4$ to get $-8$.

$$-2x<-8$$

Divide both sides by $-2$. Since $-2$ is negative, the inequality direction is changed.

$$x>\frac{-8}{-2}$$

Divide $-8$ by $-2$ to get $4$.

$$x>4$$