How to solve 2(4/3)+1(3/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(4/3)+1(3/7 | Equatix

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$$2(4/3)+1(3/7$$

$\frac{65}{21}\approx 3.095238095$

Express $2\times \frac{4}{3}$ as a single fraction.

$$\frac{2\times 4}{3}+1\times \frac{3}{7}$$

Multiply $2$ and $4$ to get $8$.

$$\frac{8}{3}+1\times \frac{3}{7}$$

Multiply $1$ and $\frac{3}{7}$ to get $\frac{3}{7}$.

$$\frac{8}{3}+\frac{3}{7}$$

Least common multiple of $3$ and $7$ is $21$. Convert $\frac{8}{3}$ and $\frac{3}{7}$ to fractions with denominator $21$.

$$\frac{56}{21}+\frac{9}{21}$$

Since $\frac{56}{21}$ and $\frac{9}{21}$ have the same denominator, add them by adding their numerators.

$$\frac{56+9}{21}$$

Add $56$ and $9$ to get $65$.

$$\frac{65}{21}$$

$\frac{5 \cdot 13}{3 \cdot 7} = 3\frac{2}{21} = 3.0952380952380953$