How to solve 2(4/9)+1(3/7)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(4/9)+1(3/7) | Equatix

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$$2(4/9)+1(3/7)$$

$\frac{83}{63}\approx 1.317460317$

Express $2\times \frac{4}{9}$ as a single fraction.

$$\frac{2\times 4}{9}+1\times \frac{3}{7}$$

Multiply $2$ and $4$ to get $8$.

$$\frac{8}{9}+1\times \frac{3}{7}$$

Multiply $1$ and $\frac{3}{7}$ to get $\frac{3}{7}$.

$$\frac{8}{9}+\frac{3}{7}$$

Least common multiple of $9$ and $7$ is $63$. Convert $\frac{8}{9}$ and $\frac{3}{7}$ to fractions with denominator $63$.

$$\frac{56}{63}+\frac{27}{63}$$

Since $\frac{56}{63}$ and $\frac{27}{63}$ have the same denominator, add them by adding their numerators.

$$\frac{56+27}{63}$$

Add $56$ and $27$ to get $83$.

$$\frac{83}{63}$$

$\frac{83}{3 ^ {2} \cdot 7} = 1\frac{20}{63} = 1.3174603174603174$