How to solve 2(7-8x)=32-10x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(7-8x)=32-10x | Equatix

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3(r+2s)=2t-4

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Question

$$2(7-8x)=32-10x$$

Solve for x

$x=-3$

Steps for Solving Linear Equation

Use the distributive property to multiply $2$ by $7-8x$.

$$14-16x=32-10x$$

Add $10x$ to both sides.

$$14-16x+10x=32$$

Combine $-16x$ and $10x$ to get $-6x$.

$$14-6x=32$$

Subtract $14$ from both sides.

$$-6x=32-14$$

Subtract $14$ from $32$ to get $18$.

$$-6x=18$$

Divide both sides by $-6$.

$$x=\frac{18}{-6}$$

Divide $18$ by $-6$ to get $-3$.

$$x=-3$$

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Question

Solve for x

Steps for Solving Linear Equation