How to solve 2((27)/(42))+3y=2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2((27)/(42))+3y=2 | Equatix

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Question

$$2( \frac{ 27 }{ 42 } )+3y=2$$

Solve for y

$y=\frac{5}{21}\approx 0.238095238$

Steps for Solving Linear Equation

Reduce the fraction $\frac{27}{42}$ to lowest terms by extracting and canceling out $3$.

$$2\times \frac{9}{14}+3y=2$$

Express $2\times \frac{9}{14}$ as a single fraction.

$$\frac{2\times 9}{14}+3y=2$$

Multiply $2$ and $9$ to get $18$.

$$\frac{18}{14}+3y=2$$

Reduce the fraction $\frac{18}{14}$ to lowest terms by extracting and canceling out $2$.

$$\frac{9}{7}+3y=2$$

Subtract $\frac{9}{7}$ from both sides.

$$3y=2-\frac{9}{7}$$

Convert $2$ to fraction $\frac{14}{7}$.

$$3y=\frac{14}{7}-\frac{9}{7}$$

Since $\frac{14}{7}$ and $\frac{9}{7}$ have the same denominator, subtract them by subtracting their numerators.

$$3y=\frac{14-9}{7}$$

Subtract $9$ from $14$ to get $5$.

$$3y=\frac{5}{7}$$

Divide both sides by $3$.

$$y=\frac{\frac{5}{7}}{3}$$

Express $\frac{\frac{5}{7}}{3}$ as a single fraction.

$$y=\frac{5}{7\times 3}$$

Multiply $7$ and $3$ to get $21$.

$$y=\frac{5}{21}$$

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