$$2( \frac{ z+2 }{ 2 } )+3=1+( \frac{ z+2 }{ 2 } )+4$$
$z=2$
$$2\left(z+2\right)+6=2+z+2+8$$
$$2z+4+6=2+z+2+8$$
$$2z+10=2+z+2+8$$
$$2z+10=4+z+8$$
$$2z+10=12+z$$
$$2z+10-z=12$$
$$z+10=12$$
$$z=12-10$$
$$z=2$$
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