How to solve 2(x-5)-3(x+1)-3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(x-5)-3(x+1)-3 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2(x-5)-3(x+1)-3$$

Evaluate

$-x-16$

Solution Steps

Use the distributive property to multiply $2$ by $x-5$.

$$2x-10-3\left(x+1\right)-3$$

Use the distributive property to multiply $-3$ by $x+1$.

$$2x-10-3x-3-3$$

Combine $2x$ and $-3x$ to get $-x$.

$$-x-10-3-3$$

Subtract $3$ from $-10$ to get $-13$.

$$-x-13-3$$

Subtract $3$ from $-13$ to get $-16$.

$$-x-16$$

Show Solution

Expand

$-x-16$

Solution Steps

Use the distributive property to multiply $2$ by $x-5$.

$$2x-10-3\left(x+1\right)-3$$

Use the distributive property to multiply $-3$ by $x+1$.

$$2x-10-3x-3-3$$

Combine $2x$ and $-3x$ to get $-x$.

$$-x-10-3-3$$

Subtract $3$ from $-10$ to get $-13$.

$$-x-13-3$$

Subtract $3$ from $-13$ to get $-16$.

$$-x-16$$

Show Solution

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Question

Evaluate

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Solution Steps