Solve 2(x+1)-3(x-2) < x+6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2(x+1)-3(x-2) < x+6$$

Solve for x

$x>1$

Solution Steps

Use the distributive property to multiply $2$ by $x+1$.

$$2x+2-3\left(x-2\right)<x+6$$

Use the distributive property to multiply $-3$ by $x-2$.

$$2x+2-3x+6<x+6$$

Combine $2x$ and $-3x$ to get $-x$.

$$-x+2+6<x+6$$

Add $2$ and $6$ to get $8$.

$$-x+8<x+6$$

Subtract $x$ from both sides.

$$-x+8-x<6$$

Combine $-x$ and $-x$ to get $-2x$.

$$-2x+8<6$$

Subtract $8$ from both sides.

$$-2x<6-8$$

Subtract $8$ from $6$ to get $-2$.

$$-2x<-2$$

Divide both sides by $-2$. Since $-2$ is negative, the inequality direction is changed.

$$x>\frac{-2}{-2}$$

Divide $-2$ by $-2$ to get $1$.

$$x>1$$