How to solve 2(x+5)-3(x-6)=40

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2(x+5)-3(x-6)=40 | Equatix

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Question

$$2(x+5)-3(x-6)=40$$

Solve for x

$x=-12$

Steps for Solving Linear Equation

Use the distributive property to multiply $2$ by $x+5$.

$$2x+10-3\left(x-6\right)=40$$

Use the distributive property to multiply $-3$ by $x-6$.

$$2x+10-3x+18=40$$

Combine $2x$ and $-3x$ to get $-x$.

$$-x+10+18=40$$

Add $10$ and $18$ to get $28$.

$$-x+28=40$$

Subtract $28$ from both sides.

$$-x=40-28$$

Subtract $28$ from $40$ to get $12$.

$$-x=12$$

Multiply both sides by $-1$.

$$x=-12$$

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Solve for x

Steps for Solving Linear Equation