Question

$$2 + 1 = 0 \quad ( 1 ) - 5 + [ 1 = 0$$

Answer

v=1/(27*e*c*g*d)

Solution


Regroup terms.
\[27evcgd=0+\]
Divide both sides by \(27\).
\[evcgd=\frac{}{27}\]
Divide both sides by \(e\).
\[vcgd=\frac{\frac{}{27}}{e}\]
Simplify  \(/27/e\)  to  \(\frac{1}{27e}\).
\[vcgd=\frac{1}{27e}\]
Divide both sides by \(c\).
\[vgd=\frac{\frac{1}{27e}}{c}\]
Simplify  \(\frac{\frac{1}{27e}}{c}\)  to  \(\frac{1}{27ec}\).
\[vgd=\frac{1}{27ec}\]
Divide both sides by \(g\).
\[vd=\frac{\frac{1}{27ec}}{g}\]
Simplify  \(\frac{\frac{1}{27ec}}{g}\)  to  \(\frac{1}{27ecg}\).
\[vd=\frac{1}{27ecg}\]
Divide both sides by \(d\).
\[v=\frac{\frac{1}{27ecg}}{d}\]
Simplify  \(\frac{\frac{1}{27ecg}}{d}\)  to  \(\frac{1}{27ecgd}\).
\[v=\frac{1}{27ecgd}\]