How to solve 2+1-8-9+5x638

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2+1-8-9+5x638 | Equatix

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Question

$$2+1-8-9+5x638$$

Evaluate

$5x_{638}-14$

Solution Steps

Add $2$ and $1$ to get $3$.

$$3-8-9+5x_{638}$$

Subtract $8$ from $3$ to get $-5$.

$$-5-9+5x_{638}$$

Subtract $9$ from $-5$ to get $-14$.

$$-14+5x_{638}$$

Show Solution

Differentiate w.r.t. x_638

$5$

Steps Using Derivative Rule for Sum

Add $2$ and $1$ to get $3$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{638}}(3-8-9+5x_{638})$$

Subtract $8$ from $3$ to get $-5$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{638}}(-5-9+5x_{638})$$

Subtract $9$ from $-5$ to get $-14$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{638}}(-14+5x_{638})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$5x_{638}^{1-1}$$

Subtract $1$ from $1$.

$$5x_{638}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$5\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$5$$