How to solve 2+24/6-8 imes3-2=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2+24/6-8\times3-2= | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$2+24/6-8 \times 3-2=$$

Evaluate

$-20$

Solution Steps

Divide $24$ by $6$ to get $4$.

$$2+4-8\times 3-2$$

Add $2$ and $4$ to get $6$.

$$6-8\times 3-2$$

Multiply $8$ and $3$ to get $24$.

$$6-24-2$$

Subtract $24$ from $6$ to get $-18$.

$$-18-2$$

Subtract $2$ from $-18$ to get $-20$.

$$-20$$

Show Solution

Factor

$-20$

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