Solve |2+[27-36+36-(-38)] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$|2+[27-36+36-(-38)]$$

Evaluate

$67$

Solution Steps

Subtract $36$ from $27$ to get $-9$.

$$|2+-9+36-\left(-38\right)|$$

Add $-9$ and $36$ to get $27$.

$$|2+27-\left(-38\right)|$$

The opposite of $-38$ is $38$.

$$|2+27+38|$$

Add $27$ and $38$ to get $65$.

$$|2+65|$$

Add $2$ and $65$ to get $67$.

$$|67|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $67$ is $67$.

$$67$$

Factor

$67$