How to solve 2+[7-36+36-(-38)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2+[7-36+36-(-38)] | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$2+[7-36+36-(-38)]$$

Evaluate

$47$

Solution Steps

Subtract $36$ from $7$ to get $-29$.

$$2+-29+36-\left(-38\right)$$

Add $-29$ and $36$ to get $7$.

$$2+7-\left(-38\right)$$

The opposite of $-38$ is $38$.

$$2+7+38$$

Add $7$ and $38$ to get $45$.

$$2+45$$

Add $2$ and $45$ to get $47$.

$$47$$

Show Solution

Factor

$47$

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