Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[2+\sqrt{1\times \sqrt{4}\sqrt{\sqrt{7}}}+\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[2+\sqrt{1\times 2\sqrt{\sqrt{7}}}+\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[2+\sqrt{1\times 2\times {7}^{\frac{1\times 1}{2\times 2}}}+\]
Simplify \(1\times 1\) to \(1\).
\[2+\sqrt{1\times 2\sqrt[2\times 2]{7}}+\]
Simplify \(2\times 2\) to \(4\).
\[2+\sqrt{1\times 2\sqrt[4]{7}}+\]
Simplify \(1\times 2\sqrt[4]{7}\) to \(2\sqrt[4]{7}\).
\[2+\sqrt{2\sqrt[4]{7}}+\]
2+sqrt(2*7^(1/4))+
