How to solve 2^ 2 (x+3+9-5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2^ 2 (x+3+9-5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2^{2}(x+3+9-5$$

Evaluate

$4\left(x+7\right)$

Solution Steps

Calculate $2$ to the power of $2$ and get $4$.

$$4\left(x+3+9-5\right)$$

Add $3$ and $9$ to get $12$.

$$4\left(x+12-5\right)$$

Subtract $5$ from $12$ to get $7$.

$$4\left(x+7\right)$$

Use the distributive property to multiply $4$ by $x+7$.

$$4x+28$$

Show Solution

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$4x+28$

Solution Steps

Calculate $2$ to the power of $2$ and get $4$.

$$4\left(x+3+9-5\right)$$

Add $3$ and $9$ to get $12$.

$$4\left(x+12-5\right)$$

Subtract $5$ from $12$ to get $7$.

$$4\left(x+7\right)$$

Use the distributive property to multiply $4$ by $x+7$.

$$4x+28$$

Show Solution

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Question

Evaluate

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Solution Steps