Question

$$2^{3}\times81\times3^{2}; 9^{2}\times[(3)^{2}]^{2}\times3^{0}$$

Answer

$$8*81*3^2;9^2*[3^2]^2*1$$

Solution


Simplify  \({2}^{3}\)  to  \(8\).
8*81*3^2;9^2*\({3}^{2}\)^2*3^0
Use Rule of Zero: \({x}^{0}=1\).
8*81*3^2;9^2*\({3}^{2}\)^2*1