$$2^{3}\times\{[(32\div4)\times2]+2\}\div3$$
$48$
$$\frac{8\left(\frac{32}{4}\times 2+2\right)}{3}$$
$$\frac{8\left(8\times 2+2\right)}{3}$$
$$\frac{8\left(16+2\right)}{3}$$
$$\frac{8\times 18}{3}$$
$$\frac{144}{3}$$
$$48$$
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$2^{4}\times 3$
