How to solve 2 ^ 4 + B ^ 4 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 ^ 4 + B ^ 4 = | Equatix

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Question

$$2^{4}+B^{4}=$$

Differentiate w.r.t. B

$4B^{3}$

Steps Using Derivative Rule for Sum

Calculate $2$ to the power of $4$ and get $16$.

$$\frac{\mathrm{d}}{\mathrm{d}B}(16+B^{4})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$4B^{4-1}$$

Subtract $1$ from $4$.

$$4B^{3}$$

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Evaluate

$B^{4}+16$

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Example

Question

Differentiate w.r.t. B

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps