$$2^{-1}[(\frac{5}{4})^{4}+(\frac{3}{5})^{-2}]\div\frac{17}{9}$$
$\frac{12025}{8704}\approx 1.381548713$
$$\frac{\frac{1}{2}\left(\left(\frac{5}{4}\right)^{4}+\left(\frac{3}{5}\right)^{-2}\right)}{\frac{17}{9}}$$
$$\frac{\frac{1}{2}\left(\frac{625}{256}+\left(\frac{3}{5}\right)^{-2}\right)}{\frac{17}{9}}$$
$$\frac{\frac{1}{2}\left(\frac{625}{256}+\frac{25}{9}\right)}{\frac{17}{9}}$$
$$\frac{\frac{1}{2}\times \frac{12025}{2304}}{\frac{17}{9}}$$
$$\frac{\frac{12025}{4608}}{\frac{17}{9}}$$
$$\frac{12025}{4608}\times \frac{9}{17}$$
$$\frac{12025}{8704}$$
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$\frac{5 ^ {2} \cdot 13 \cdot 37}{2 ^ {9} \cdot 17} = 1\frac{3321}{8704} = 1.3815487132352942$