Question

$$2 \sqrt{ 20 } -2 \sqrt{ 45 } + \frac{ 1 }{ 4 } \sqrt{ 16 }$$

Answer

-2*sqrt(5)+1

Solution


Simplify  \(\sqrt{20}\)  to  \(2\sqrt{5}\).
\[2\times 2\sqrt{5}-2\sqrt{45}+\frac{1}{4}\sqrt{16}\]
Simplify  \(\sqrt{45}\)  to  \(3\sqrt{5}\).
\[2\times 2\sqrt{5}-2\times 3\sqrt{5}+\frac{1}{4}\sqrt{16}\]
Since \(4\times 4=16\), the square root of \(16\) is \(4\).
\[2\times 2\sqrt{5}-2\times 3\sqrt{5}+\frac{1}{4}\times 4\]
Simplify  \(2\times 2\sqrt{5}\)  to  \(4\sqrt{5}\).
\[4\sqrt{5}-2\times 3\sqrt{5}+\frac{1}{4}\times 4\]
Simplify  \(2\times 3\sqrt{5}\)  to  \(6\sqrt{5}\).
\[4\sqrt{5}-6\sqrt{5}+\frac{1}{4}\times 4\]
Cancel \(4\).
\[4\sqrt{5}-6\sqrt{5}+1\]
Collect like terms.
\[(4\sqrt{5}-6\sqrt{5})+1\]
Simplify.
\[-2\sqrt{5}+1\]

Decimal Form: -3.472136