$$2 \times [(-12+36) \div 6+(8-5) \div (3)]-6$$
$4$
$$2\left(\frac{24}{6}+\frac{8-5}{3}\right)-6$$
$$2\left(4+\frac{8-5}{3}\right)-6$$
$$2\left(4+\frac{3}{3}\right)-6$$
$$2\left(4+1\right)-6$$
$$2\times 5-6$$
$$10-6$$
$$4$$
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$2^{2}$
