$$2 \times 4x+x$$
$9x$
$$8x+x$$
$$9x$$
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$9$
$$\frac{\mathrm{d}}{\mathrm{d}x}(8x+x)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(9x)$$
$$9x^{1-1}$$
$$9x^{0}$$
$$9\times 1$$
$$9$$