Question

$$2\ x\ \log\ 5+\log\ 4=\log_{25}^{8}-\log^{2}$$

Answer

$$x=((log(25,^8)-log()^2-log(4))/2)/log(5)$$

Solution


Subtract \(\log{4}\) from both sides.
\[2x\log{5}=\log_{25}{{}^{8}}-{\log{}}^{2}-\log{4}\]
Divide both sides by \(2\).
\[x\log{5}=\frac{\log_{25}{{}^{8}}-{\log{}}^{2}-\log{4}}{2}\]
Divide both sides by \(\log{5}\).
\[x=\frac{\frac{\log_{25}{{}^{8}}-{\log{}}^{2}-\log{4}}{2}}{\log{5}}\]