How to solve ) 2x -4x+3x 5 4x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ) 2x -4x+3x 5 4x | Equatix

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Question

$$2 x - 4 x + 3 x + 5 x + 5 4 x + x + x + 0$$

Evaluate

$28x$

Solution Steps

Combine $2x$ and $-4x$ to get $-2x$.

$$-2x+3x+5x+5\times 4x+x+x+0$$

Combine $-2x$ and $3x$ to get $x$.

$$x+5x+5\times 4x+x+x+0$$

Combine $x$ and $5x$ to get $6x$.

$$6x+5\times 4x+x+x+0$$

Multiply $5$ and $4$ to get $20$.

$$6x+20x+x+x+0$$

Combine $6x$ and $20x$ to get $26x$.

$$26x+x+x+0$$

Combine $26x$ and $x$ to get $27x$.

$$27x+x+0$$

Combine $27x$ and $x$ to get $28x$.

$$28x+0$$

Anything plus zero gives itself.

$$28x$$

Show Solution

Differentiate w.r.t. x

$28$

Steps Using Definition of a Derivative

Combine $2x$ and $-4x$ to get $-2x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-2x+3x+5x+5\times 4x+x+x+0)$$

Combine $-2x$ and $3x$ to get $x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+5x+5\times 4x+x+x+0)$$

Combine $x$ and $5x$ to get $6x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x+5\times 4x+x+x+0)$$

Multiply $5$ and $4$ to get $20$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x+20x+x+x+0)$$

Combine $6x$ and $20x$ to get $26x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(26x+x+x+0)$$

Combine $26x$ and $x$ to get $27x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(27x+x+0)$$

Combine $27x$ and $x$ to get $28x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(28x+0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(28x)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$28x^{1-1}$$

Subtract $1$ from $1$.

$$28x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$28\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$28$$