$$2 x - 4 x ^ { 2 } + 3 x + 5 4 x ^ { 2 } + x ^ { 2 } + x + 6$$
$17x^{2}+6x+6$
$$5x-4x^{2}+5\times 4x^{2}+x^{2}+x+6$$
$$5x-4x^{2}+20x^{2}+x^{2}+x+6$$
$$5x+16x^{2}+x^{2}+x+6$$
$$5x+17x^{2}+x+6$$
$$6x+17x^{2}+6$$
Show Solution
Hide Solution
$34x+6$
$$\frac{\mathrm{d}}{\mathrm{d}x}(5x-4x^{2}+5\times 4x^{2}+x^{2}+x+6)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(5x-4x^{2}+20x^{2}+x^{2}+x+6)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+16x^{2}+x^{2}+x+6)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+17x^{2}+x+6)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(6x+17x^{2}+6)$$
$$6x^{1-1}+2\times 17x^{2-1}$$
$$6x^{0}+2\times 17x^{2-1}$$
$$6x^{0}+34x^{2-1}$$
$$6x^{0}+34x^{1}$$
$$6x^{0}+34x$$
$$6\times 1+34x$$
$$6+34x$$
