Solve of the following 2x^ 2 -\ 4(2x-2)-(4x^ 2 - overline 3+2 )\ mply the following

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Question

$$2 x ^ { 2 } - \{ 4 ( 2 x - 2 ) - ( 4 x ^ { 2 } - 3 + 2 ) \}$$

Evaluate

$6x^{2}-8x+7$

Solution Steps

Use the distributive property to multiply $4$ by $2x-2$.

$$2x^{2}-\left(8x-8-\left(4x^{2}-3+2\right)\right)$$

Add $-3$ and $2$ to get $-1$.

$$2x^{2}-\left(8x-8-\left(4x^{2}-1\right)\right)$$

To find the opposite of $4x^{2}-1$, find the opposite of each term.

$$2x^{2}-\left(8x-8-4x^{2}+1\right)$$

Add $-8$ and $1$ to get $-7$.

$$2x^{2}-\left(8x-7-4x^{2}\right)$$

To find the opposite of $8x-7-4x^{2}$, find the opposite of each term.

$$2x^{2}-8x+7+4x^{2}$$

Combine $2x^{2}$ and $4x^{2}$ to get $6x^{2}$.

$$6x^{2}-8x+7$$

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$6x^{2}-8x+7$

Solution Steps

Use the distributive property to multiply $4$ by $2x-2$.

$$2x^{2}-\left(8x-8-\left(4x^{2}-3+2\right)\right)$$

Add $-3$ and $2$ to get $-1$.

$$2x^{2}-\left(8x-8-\left(4x^{2}-1\right)\right)$$

To find the opposite of $4x^{2}-1$, find the opposite of each term.

$$2x^{2}-\left(8x-8-4x^{2}+1\right)$$

Add $-8$ and $1$ to get $-7$.

$$2x^{2}-\left(8x-7-4x^{2}\right)$$

To find the opposite of $8x-7-4x^{2}$, find the opposite of each term.

$$2x^{2}-8x+7+4x^{2}$$

Combine $2x^{2}$ and $4x^{2}$ to get $6x^{2}$.

$$6x^{2}-8x+7$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

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Linear Algebra

Chemistry

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