How to solve 20/7+27/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 20/7+27/3 | Equatix

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Question

$$20/7+27/3$$

Evaluate

$\frac{83}{7}\approx 11.857142857$

Solution Steps

Divide $27$ by $3$ to get $9$.

$$\frac{20}{7}+9$$

Convert $9$ to fraction $\frac{63}{7}$.

$$\frac{20}{7}+\frac{63}{7}$$

Since $\frac{20}{7}$ and $\frac{63}{7}$ have the same denominator, add them by adding their numerators.

$$\frac{20+63}{7}$$

Add $20$ and $63$ to get $83$.

$$\frac{83}{7}$$

Show Solution

Factor

$\frac{83}{7} = 11\frac{6}{7} = 11.857142857142858$

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