$$20 - 3 b + 4 c , 5 b - 4 c 3 a + 5 c$$
$\left(3b-4c-20\right)\left(5c+5b-4ac_{3}\right)$
$$\left(3b-4c-20\right)\left(5c+5b-4ac_{3}\right)$$
$$-12abc_{3}+16acc_{3}+80ac_{3}+15b^{2}-5bc-100b-20c^{2}-100c$$
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$20+4c-3b,5c+5b-4ac_{3}$
