How to solve 20x + 95 = 5x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 20x + 95 = 5x | Equatix

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$$20x+95=5x$$

$x = -\frac{19}{3} = -6\frac{1}{3} \approx -6.333333333$

Subtract $5x$ from both sides.

$$20x+95-5x=0$$

Combine $20x$ and $-5x$ to get $15x$.

$$15x+95=0$$

Subtract $95$ from both sides. Anything subtracted from zero gives its negation.

$$15x=-95$$

Divide both sides by $15$.

$$x=\frac{-95}{15}$$

Reduce the fraction $\frac{-95}{15}$ to lowest terms by extracting and canceling out $5$.

$$x=-\frac{19}{3}$$