Solve 20y ^ 3 + 3y + 8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$20y^{3}+3y+8$$

Differentiate w.r.t. y

$60y^{2}+3$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$3\times 20y^{3-1}+3y^{1-1}$$

Multiply $3$ times $20$.

$$60y^{3-1}+3y^{1-1}$$

Subtract $1$ from $3$.

$$60y^{2}+3y^{1-1}$$

Subtract $1$ from $1$.

$$60y^{2}+3y^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$60y^{2}+3\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$60y^{2}+3$$

Evaluate

$20y^{3}+3y+8$