How to solve 21-xSIx=10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 21-xSIx=10 | Equatix

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Question

$$21-xSIx=10$$

Solve for I

$I=\frac{11}{Sx^{2}}$
$x\neq 0\text{ and }S\neq 0$

Steps for Solving Linear Equation

Multiply $x$ and $x$ to get $x^{2}$.

$$21-x^{2}SI=10$$

Subtract $21$ from both sides.

$$-x^{2}SI=10-21$$

Subtract $21$ from $10$ to get $-11$.

$$-x^{2}SI=-11$$

The equation is in standard form.

$$\left(-Sx^{2}\right)I=-11$$

Divide both sides by $-x^{2}S$.

$$\frac{\left(-Sx^{2}\right)I}{-Sx^{2}}=-\frac{11}{-Sx^{2}}$$

Dividing by $-x^{2}S$ undoes the multiplication by $-x^{2}S$.

$$I=-\frac{11}{-Sx^{2}}$$

Divide $-11$ by $-x^{2}S$.

$$I=\frac{11}{Sx^{2}}$$

Show Solution

Solve for S

$S=\frac{11}{Ix^{2}}$
$x\neq 0\text{ and }I\neq 0$

Steps for Solving Linear Equation

Multiply $x$ and $x$ to get $x^{2}$.

$$21-x^{2}SI=10$$

Subtract $21$ from both sides.

$$-x^{2}SI=10-21$$

Subtract $21$ from $10$ to get $-11$.

$$-x^{2}SI=-11$$

The equation is in standard form.

$$\left(-Ix^{2}\right)S=-11$$

Divide both sides by $-x^{2}I$.

$$\frac{\left(-Ix^{2}\right)S}{-Ix^{2}}=-\frac{11}{-Ix^{2}}$$

Dividing by $-x^{2}I$ undoes the multiplication by $-x^{2}I$.

$$S=-\frac{11}{-Ix^{2}}$$

Divide $-11$ by $-x^{2}I$.

$$S=\frac{11}{Ix^{2}}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for I

Steps for Solving Linear Equation

Solve for S

Steps for Solving Linear Equation