Question

$$[21 \times { 3 }^{ 0 } -5 \times { 2 }^{ 2 } -4 \times { 2 }^{ -1 } + { 5 }^{ 0 } ]$$

Answer

$$-22+[21+5^0]$$

Solution


Use Rule of Zero: \({x}^{0}=1\).
\(21\times 1-5\times {2}^{2}-4\times {2}^{-1}+{5}^{0}\)
Simplify  \({2}^{2}\)  to  \(4\).
\(21\times 1-5\times 4-4\times {2}^{-1}+{5}^{0}\)
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\(21\times 1-5\times 4-4\times \frac{1}{2}+{5}^{0}\)
\(21-5\times 4-4\times \frac{1}{2}+{5}^{0}\)
Simplify  \(5\times 4\)  to  \(20\).
\(21-20-4\times \frac{1}{2}+{5}^{0}\)
Simplify  \(4\times \frac{1}{2}\)  to  \(\frac{4}{2}\).
\(21-20-\frac{4}{2}+{5}^{0}\)
Simplify  \(\frac{4}{2}\)  to  \(2\).
\(21-20-2+{5}^{0}\)
-22+\(21+{5}^{0}\)