$$21\times8\div q=$$
$-\frac{168}{q^{2}}$
$$\frac{\mathrm{d}}{\mathrm{d}q}(\frac{168}{q})$$
$$-168q^{-1-1}$$
$$-168q^{-2}$$
Show Solution
Hide Solution
$\frac{168}{q}$
$$\frac{168}{q}$$