Consider $1728a^{3}+1$. Rewrite $1728a^{3}+1$ as $\left(12a\right)^{3}+1^{3}$. The sum of cubes can be factored using the rule: $p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right)$.
$$\left(12a+1\right)\left(144a^{2}-12a+1\right)$$
Rewrite the complete factored expression. Polynomial $144a^{2}-12a+1$ is not factored since it does not have any rational roots.
