$$220V.110$$
$24.2$
$$\frac{\mathrm{d}}{\mathrm{d}V}(24.2V)$$
$$24.2V^{1-1}$$
$$24.2V^{0}$$
$$24.2\times 1$$
$$24.2$$
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$\frac{121V}{5}$
$$24.2V$$