How to solve 22468 * 23579

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 22468 * 23579 | Equatix

Question

$$22468\times23579$$

Evaluate

$529772972$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times9999}22468\\\underline{\times\phantom{9999}23579}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 22468 with 9. Write the result 202212 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}22468\\\underline{\times\phantom{9999}23579}\\\phantom{\times999}202212\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 22468 with 7. Write the result 157276 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}22468\\\underline{\times\phantom{9999}23579}\\\phantom{\times999}202212\\\phantom{\times99}157276\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 22468 with 5. Write the result 112340 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}22468\\\underline{\times\phantom{9999}23579}\\\phantom{\times999}202212\\\phantom{\times99}157276\phantom{9}\\\phantom{\times9}112340\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 22468 with 3. Write the result 67404 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times9999}22468\\\underline{\times\phantom{9999}23579}\\\phantom{\times999}202212\\\phantom{\times99}157276\phantom{9}\\\phantom{\times9}112340\phantom{99}\\\phantom{\times9}67404\phantom{999}\\\end{array}$$

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 22468 with 2. Write the result 44936 at the end leaving 4 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{2}\times 17\times 19\times 41\times 73\times 137$

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Steps For Long Multiplication

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