$$22n^{2}\div2n^{3}$$
$11n^{5}$
$$11n^{2}n^{3}$$
$$11n^{5}$$
Show Solution
Hide Solution
$55n^{4}$
$$\frac{\mathrm{d}}{\mathrm{d}n}(11n^{2}n^{3})$$
$$\frac{\mathrm{d}}{\mathrm{d}n}(11n^{5})$$
$$5\times 11n^{5-1}$$
$$55n^{5-1}$$
$$55n^{4}$$