How to solve 23-(-+5)+t2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 23-(-+5)+t2 | Equatix

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Question

$$23-(-+5)+t2$$

Evaluate

$t_{2}+28$

Show Solution

Differentiate w.r.t. t_2

$1$

Steps Using Derivative Rule for Sum

The opposite of $-5$ is $5$.

$$\frac{\mathrm{d}}{\mathrm{d}t_{2}}(23+5+t_{2})$$

Add $23$ and $5$ to get $28$.

$$\frac{\mathrm{d}}{\mathrm{d}t_{2}}(28+t_{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$t_{2}^{1-1}$$

Subtract $1$ from $1$.

$$t_{2}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. t_2

Steps Using Derivative Rule for Sum