How to solve 2304 imes387

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2304\times387 | Equatix

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Question

$$2304 \times 387$$

Evaluate

$891648$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}2304\\\underline{\times\phantom{999}387}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2304 with 7. Write the result 16128 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}2304\\\underline{\times\phantom{999}387}\\\phantom{\times9}16128\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2304 with 8. Write the result 18432 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}2304\\\underline{\times\phantom{999}387}\\\phantom{\times9}16128\\\phantom{\times}18432\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2304 with 3. Write the result 6912 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}2304\\\underline{\times\phantom{999}387}\\\phantom{\times9}16128\\\phantom{\times}18432\phantom{9}\\\underline{\phantom{\times}6912\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}2304\\\underline{\times\phantom{999}387}\\\phantom{\times9}16128\\\phantom{\times}18432\phantom{9}\\\underline{\phantom{\times}6912\phantom{99}}\\\phantom{\times}891648\end{array}$$

Show Solution

Factor

$2^{8}\times 3^{4}\times 43$