Solve b ) Subtract 238g from 1kg 25g, giving your answer in kg. | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$238 258$$

Evaluate

$61404$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}238\\\underline{\times\phantom{99}258}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 238 with 8. Write the result 1904 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}238\\\underline{\times\phantom{99}258}\\\phantom{\times9}1904\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 238 with 5. Write the result 1190 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}238\\\underline{\times\phantom{99}258}\\\phantom{\times9}1904\\\phantom{\times}1190\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 238 with 2. Write the result 476 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}238\\\underline{\times\phantom{99}258}\\\phantom{\times9}1904\\\phantom{\times}1190\phantom{9}\\\underline{\phantom{\times}476\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}238\\\underline{\times\phantom{99}258}\\\phantom{\times9}1904\\\phantom{\times}1190\phantom{9}\\\underline{\phantom{\times}476\phantom{99}}\\\phantom{\times}61404\end{array}$$

Factor

$2^{2}\times 3\times 7\times 17\times 43$