How to solve 239 imes875648

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 239\times875648 | Equatix

Question

$$239 \times 875648$$

Evaluate

$209279872$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999999}239\\\underline{\times\phantom{999}875648}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 8. Write the result 1912 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}239\\\underline{\times\phantom{999}875648}\\\phantom{\times99999}1912\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 4. Write the result 956 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}239\\\underline{\times\phantom{999}875648}\\\phantom{\times99999}1912\\\phantom{\times99999}956\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 6. Write the result 1434 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}239\\\underline{\times\phantom{999}875648}\\\phantom{\times99999}1912\\\phantom{\times99999}956\phantom{9}\\\phantom{\times999}1434\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 5. Write the result 1195 at the end leaving 3 spaces to the right like this.

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 7. Write the result 1673 at the end leaving 4 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}239\\\underline{\times\phantom{999}875648}\\\phantom{\times99999}1912\\\phantom{\times99999}956\phantom{9}\\\phantom{\times999}1434\phantom{99}\\\phantom{\times99}1195\phantom{999}\\\phantom{\times9}1673\phantom{9999}\\\end{array}$$

Now multiply the first number with the $6^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 239 with 8. Write the result 1912 at the end leaving 5 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{7}\times 239\times 6841$

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Steps For Long Multiplication

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