1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 23x68= | Equatix

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Question

$$23x68=$$

Evaluate

$23x_{68}$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}23\\\underline{\times\phantom{99}68}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 23 with 8. Write the result 184 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}23\\\underline{\times\phantom{99}68}\\\phantom{\times9}184\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 23 with 6. Write the result 138 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}23\\\underline{\times\phantom{99}68}\\\phantom{\times9}184\\\underline{\phantom{\times}138\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}23\\\underline{\times\phantom{99}68}\\\phantom{\times9}184\\\underline{\phantom{\times}138\phantom{9}}\\\phantom{\times}1564\end{array}$$

Show Solution

Differentiate w.r.t. x_68

$23$

Steps Using Definition of a Derivative

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$23x_{68}^{1-1}$$

Subtract $1$ from $1$.

$$23x_{68}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$23\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$23$$